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Mathematically this is a nothing, but it's fun and I hadn't seen it before. Pick a number, say 852143, and multiply it by 99, giving $$84362157.$$ Now break this up into two-digit chunks: $$84\qquad 36\qquad 21\qquad 57$$ (If there is an odd number of digits, put the leftmost one in a chunk by itself.) Add up the chunks: $$84 + 36 + 21 + 57 = 198$$ Repeat the process: $$1 + 98 = 99$$ You will always finish at 99. This same method can be used to test a number to see if it is divisible by 99: you can start with any number you like, and you will end at 99 if and only if the number you started with is a multiple of 99. (If the starting and ending numbers are !!s!! and !!e!!, then !!s\equiv e\pmod{99}!!.) The trick is, of course, completely analogous to the test for divisibility by 9. Maybe you know some mathematical kid who has recently learned the divisibility-by-9 test and would enjoy seeing this version.
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